Hello,
I have a data array like:
x = [0, 0, 45, 43, 42, 41, 0 , 0 , 0, 0, 45, 43, 42, 41 ];
In my data points, 2 times my data became non-zero. Which I call them an "event".
I want my code to calculates the number of events as "2".
and calculate the sume of numbers at each event.
I'd appreciate your help at this matter.
Thanks,

 Réponse acceptée

Matt J
Matt J le 10 Juil 2019
Modifié(e) : Matt J le 10 Juil 2019

0 votes

Apply the suggestions in this thread to A=logical(x)+1.

4 commentaires

Thanks Matt for your prompt response! Actually my problem is much more complicated than this.I just simplified it. I attached a screenshot of my actual data.
I wrote this code,
x = [1, 2, 45, 43, 42, 41, 6 , 2, 7];
for i = 1 : length(x);
if x(i) > 10;
i
end
i = i + 4;
end
I want my code to sweep data, as soon as it saw a data greater than 10, print it and skip 4 points after it, then continue sweeping to find the next point greater than 10.
Ideal answer: 45
What this code gives: 45, 43, 42, 41
Matt J
Matt J le 10 Juil 2019
Just use a while loop, then:
x = [1, 2, 45, 43, 42, 41, 6 , 2, 7];
i=0;
while i<length(x)
i=i+1;
if x(i) > 10;
x(i)
i = i + 3;
end
end
Matt J
Matt J le 10 Juil 2019
Sarah's comment relocated here
Perfect! Works very well!
Thank you very much, Matt!
Matt J
Matt J le 10 Juil 2019
You're welcome. Please Accept-click the answer, though, to certify that we solved it.

Connectez-vous pour commenter.

Plus de réponses (1)

Image Analyst
Image Analyst le 10 Juil 2019

0 votes

Try this (requires the Image Processing Toolbox, which you probably already have):
x = [0, 0, 45, 43, 42, 41, 0 , 0 , 0, 0, 45, 43, 42, 41 ];
% Count number of non-zero regions: (requires Image Processing Toolbox)
[~, numNonZeroRegions] = bwlabel(x)
% Compute sum of values
props = regionprops(x>0, x, 'PixelValues');
sumOfValues = sum(vertcat(props.PixelValues), 2)

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by