# How can I solve a nonlinear model using Newton Raphson ?

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Mallouli Marwa le 15 Juil 2019
Commenté : Mallouli Marwa le 25 Jan 2020
Hi
How can I solve this nonlinear model using Newton Raphson ?
x1 +x2^2 +cos (x3) = 2
x1 +sin (x2) + x3^3 = 1
x3 +x2^3+x3^3 = 4
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### Réponse acceptée

Stephan le 25 Jan 2020
One way:
result = fsolve(@fun,[1 1 1])
function F = fun(x)
F(1) = x(1) + x(2).^2 + cos(x(3)) - 2;
F(2) = x(1) + sin(x(2)) + x(3).^3 - 1;
F(3) = x(3) +x(2).^3 + x(3).^3 - 4;
end
gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
result =
-0.5583 1.3732 0.8329
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John D'Errico le 25 Jan 2020
The best way to solve it. Don't use Newton-Raphson at all. :)
Mallouli Marwa le 25 Jan 2020
If I want to use Newton Raphson.
How can we change it ?

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