How to illustrate a cell array

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Naza Karim
Naza Karim le 16 Juil 2019
Commenté : Naza Karim le 17 Juil 2019
I have the following cel array:
x{1}=[0 0 0 0];
x{2}=[0 0 -1 0 0];
x{3}=[0 0 0 1 1 0];
x{4}=[0 0 1 1 0];
x{5}=[-1 -1 0 -1];
Which supposed to represent the state of Abalone game board, like this:
abalone4.png
Where zeros mean empty cell, -1's mean occupied by green marble, and 1's occupied by blues.
Is there any possible way to illustrate the board using my cell array?
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Naza Karim
Naza Karim le 16 Juil 2019
I am aware. I just have no idea if there is any possible way to draw such a customised figure. Thank you though for pointing to viscircles function.
Joel Handy
Joel Handy le 16 Juil 2019
Modifié(e) : Joel Handy le 16 Juil 2019
It can definitely be done. viscircles should let you create a figure with all of the circles. The fill function will let you plot the hexagon. Placing all of the shapes should be inde[endant of X. all you need to do while plotting the board is refer to your cell array to choose colors.

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Stephen23
Stephen23 le 16 Juil 2019
Modifié(e) : Stephen23 le 16 Juil 2019
There are no doubt many ways of doing this, one relatively intuitive way would be to use scatter. This should get you started (but it is not intended to be final code):
x{1} = [0,0,0,0];
x{2} = [0,0,-1,0,0];
x{3} = [0,0,0,1,1,0];
x{4} = [0,0,1,1,0];
x{5} = [-1,-1,0,-1];
% Hexagon:
Px = [-2,2,3.7,2,-2,-3.7,-2];
Py = [-6,-6,-3,0,0,-3,-6];
patch(Px,Py,0.6*[1,1,1])
hold on
% Circles:
Fx = @(v)(1:numel(v))-numel(v)/2-1/2;
Fy = @(v,n)-v*ones(1,n);
Cx = cellfun(Fx,x,'uni',0);
Cy = arrayfun(Fy,1:numel(x),cellfun('length',x),'uni',0);
Sh = scatter([Cx{:}],[Cy{:}],1024,[x{:}],'filled')
% Colors:
caxis([-1,1])
colormap([0,0.8,0;1,1,1;0.2,0.2,1])
set(gca,'visible','off')
You could also hard-code the X and Y values, which would no doubt simplify the code.
Note that you can change the colors simply by updating the scatter object's CData property (i.e. you do not need to replot everything when you change the circle colors):
  1 commentaire
Naza Karim
Naza Karim le 17 Juil 2019
Thank you! this indeed helps a lot.

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