how to find the number of 1 in a single column?

My input is

0 0 0 0 1 0 0 1 1 0 0 0 1 0

I should find how many 1 is present

[Azzi Abdelmalek]

is it a string ?

[Azzi Abdelmalek]

what is the real question?

Answer 1

[Jan]

If it is a string:

c = '0 0 0 0 1 0 0 1 1 0 0 0 1 0';
s = sum(c == '1');
% or:
s = length(strfind(c, '1');

if it is a numeric vector:

c = [0 0 0 0 1 0 0 1 1 0 0 0 1 0];
s = sum(c);  % as Jose-Luis has suggested already
% or:
s = nnz(c);

Answer 2

[José-Luis]

your_answer = sum(your_input)

Answer 3

[Azzi Abdelmalek]

 c='0 0 0 0 1 0 0 1 1 0 0 0 1 0'
 sum(str2num(c))

Answer 4

[Sivakumaran Chandrasekaran]

Thanks for all replies...

1 1

     1     2
     3     1
     2     1
     3     1
     1     2
     3     2
     2     1
     3     1
     2     1
     3     2
     2     2
     3     1
     2     2

Answer 5

[Sivakumaran Chandrasekaran]

thats my input matrix.. let me take query input as 1 1... now i have to check this 1 1 with all the rows of the given input matrix.. I have find the rows which matches this input.

[Sivakumaran Chandrasekaran]

when i take the first row as the query one, and if i found it is matching with 5th, then output should be displayed as [1,5]

[José-Luis]

your_result = find(ismember(your_matrix,[1 2],'rows'))';

Answer 6

[Matt Tearle]

idx = find(all(bsxfun(@eq,x,y),2));

where x is your matrix and y is your test vector (eg y = x(1,:), in your example). For example

x = randi(4,1000,5);
y = x(3,:);
idx = find(all(bsxfun(@eq,x,y),2))