I have the following cell structure:
1x30 double
1x23 double
1x23 double
1x23 double
1x23 double
1x23 double
1x23 double
1x25 double
1x35 double
I want to find whether a number is present in one of these and want to know the index of that. So for instance the number 5 is present in double 1, 5 and 7, so the output should be [1 5 7]. Can this be done?

4 commentaires

Alex Sune
Alex Sune le 7 Août 2019
Take a look to cellfun
madhan ravi
madhan ravi le 7 Août 2019
Unclear, attach your data as .mat file.
KSSV
KSSV le 7 Août 2019
Read about ismember, find.
Adam
Adam le 7 Août 2019
Modifié(e) : Adam le 7 Août 2019
Off the top of my head, something like this may work:
find( cellfun( @(x) any( find( x == 5 ) ), myCell, 'UniformOutput', false ) )
where myCell is your cell array.
At least it may give you ideas to get to the right solution, though I'm sure someone else will quickly come along with a correct or better solution if this is not it!

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 Réponse acceptée

madhan ravi
madhan ravi le 7 Août 2019
Modifié(e) : madhan ravi le 7 Août 2019

0 votes

v=cellfun(@(x) any( x == 5 ), yourcell);
Wanted = find(v) % Adam was almost right , but a minute tweak

3 commentaires

Stephen23
Stephen23 le 7 Août 2019
Modifié(e) : Stephen23 le 7 Août 2019
Simpler:
find(cellfun(@(x)any(x(:)==5),yourcell))
That any(find(...)) syntax is rather obfuscated, and should be avoided.
madhan ravi
madhan ravi le 7 Août 2019
Thank you Stephen!
JamJan
JamJan le 7 Août 2019
Thank you guys!

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