Modifying a structure array
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Hi. I am working with a structure array, and I want to modify the structure based on a condition on the field entries.
For example,
Here is the input,
S(1).f1=[1:100] and S(2).f2=[2:101];
S(2).f1=[40:120] and S(2).f2=[60:140]
S(3).f1=...... and S(3).f2=.....
S(4).f1=.... and S(4).f2=.....
.
.
S(i).f1=.... and S(i).f2=....
Can anyone suggest me some smart way to do this.
Conditions on input Output
S(1).f1>=0 and S(1).f1<=50 then ------> S(1).f1=[1:50] and S(1).f2=[2:51]
S(1).f1>50 and S(1).f1<=100 then ------>S(2).f1=[51:100] and S(2).f2=[52:101]
.... so on
Now, the same process for original/input S(2).f1, S(3).f1 .... S(i).f1 to re-form the structure.
After, modification the final step is to delete S(i) if the size of S(i).f1 is < 5.
Réponse acceptée
Plus de réponses (1)
Since you don't provide any indication of how you want this to work for struct array input, you'll have to modify this code yourself.
S=struct;
S(1).f1=[2,3,4,5,6,7,8,10,14,16,18,20];
S(1).f2=[3,6,9,12,15,18,21,24,27,30,33,36];
L=S(1).f1<=10;
if sum(L)>=5
S(2).f1=S(1).f1(L);
S(2).f2=S(1).f2(L);
end
S(1).f1(L)=[];S(1).f2(L)=[];
Edit:
%create input struct
S=struct;
S(1).f1=5*[2,3,4,5,6,7,8,10,14,16,18,20];
S(1).f2=5*[3,6,9,12,15,18,21,24,27,30,33,36];
S(2).f1=40:120;S(2).f2=60:140;
S(3).f1=20:100;S(3).f2=40:120;
%create the cell array that will hold the struct elements
c=cell(2,numel(S));
for n=1:numel(S)
c{1,n}=S(n);
L=S(n).f1<=50;
if sum(L)>=5
c{2,n}.f1=S(n).f1(L);
c{2,n}.f2=S(n).f2(L);
end
c{1,n}.f1(L)=[];c{1,n}.f2(L)=[];
end
%reshape back to a struct
S=[c{:}];
4 commentaires
Rik
le 12 Août 2019
That is not working because you use && instead of &. The single operator should be used for arrays, the double operator for scalars.
For numbered fields you could use a loop like this:
for n=1:5
S.(sprintf('f%d',n)) = rand;
end
Rik
le 12 Août 2019
The .() syntax works for char array inputs (and scalar strings).
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