how to generate loop for given program

my dataset buttLoop3 is 24000x4 and i want to find out zero crossing of it...

i want to do below work in loop instead of typing it 4 time

zcd = dsp.ZeroCrossingDetector % calling function to detect zero count... 
zcdOut = zcd(buttLoop3);  % it counts how many times signals cross zero



y1 = buttLoop3(:,1)  ;  % filtered signal
zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0); % Returns Approximate Zero-Crossing Indices Of Argument Vector
xi1 = zci(y1); % zero crossing indices command
for k = 1:numel(xi1)-1 
ti1(k) = interp1(y1([xi1(k) xi1(k)+1]), t([xi1(k) xi1(k)+1]), 0); % Interpolate To Find ‘t’ At ‘y=0 ’ 
end



y2 = buttLoop3(:,2)  ;  % filtered signal
zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0); % Returns Approximate Zero-Crossing Indices Of Argument Vector
xi2 = zci(y2); % zero crossing indices command
for k = 1:numel(xi2)-1 
ti2(k) = interp1(y2([xi2(k) xi2(k)+1]), t([xi2(k) xi2(k)+1]), 0); % Interpolate To Find ‘t’ At ‘y=0 ’ 
end


y3 = buttLoop3(:,3)  ;  % filtered signal
zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0); % Returns Approximate Zero-Crossing Indices Of Argument Vector
xi3 = zci(y3); % zero crossing indices command
for k = 1:numel(xi3)-1 
ti3(k) = interp1(y3([xi3(k) xi3(k)+1]), t([xi3(k) xi3(k)+1]), 0); % Interpolate To Find ‘t’ At ‘y=0 ’ 
end


y4 = buttLoop3(:,4)  ;  % filtered signal
zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0); % Returns Approximate Zero-Crossing Indices Of Argument Vector
xi4 = zci(y4); % zero crossing indices command
for k = 1:numel(xi4)-1 
ti4(k) = interp1(y4([xi4(k) xi4(k)+1]), t([xi4(k) xi4(k)+1]), 0); % Interpolate To Find ‘t’ At ‘y=0 ’ 
end

Answer 1

[darova]

Then use for loop

% a(1) = 2;
% a(2) = 3;
% a(3) = 4;
% a(4) = 5;

for i = 1:4
    a(i) = i+1; 
end

Simple

[Ali Asghar]

dear

kindly suggest complete code.

like

or i = 1:4

a(i) = i+1;

y(i) = filter_datawindow(:,i) ; % filtered signal

zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0); % Returns Approximate Zero-Crossing Indices Of Argument Vector

x(i) = zci(y(i)); % zero crossing indices command

for k = 1:numel(x(i))-1

ti1(k) = interp1(y(i)([x(i)(k) x(i)(k)+1]), t([x(i)(k) x(i)(k)+1]), 0); % Interpolate To Find ‘t’ At ‘y=0 ’

end

end

this give error

[darova]

It's because you trying to assign

x(i) = [1 2 3];

You don't need indexes in this case

y = filter_datawindow(:,i)  ;  % filtered signal