Placing a constant through a column

Imagine this

A=(1:30)';
B=(31:60)';
C=(61:90)';
D=[A B C];
S  = numel(B);
xx = reshape(B(1:S - mod(S, 3)), 3, []);
BB  = sum(xx, 1).' / 3;
F=[A B C BB];

You will notice F is not possible because BB has just 10 variables (Dimensions of arrays being concatenated are not consistent.)

What I need to do is make each value in BB constant for 3 rows so that F can become possible.

Answer 1

[madhan ravi]

repmat(BB,3,1)

[DARLINGTON ETAJE]

Nice try...almost there...this is how the BB should finally be

32
32
32
35
35
35
38
38
38
41
41
41
44
44
44
47
47
47
50
50
50
53
53
53
56
56
56
59
59
59

[madhan ravi]

Use:

repelem(BB,3)

[DARLINGTON ETAJE]

Thank you...you're such a blessing