Effacer les filtres
Effacer les filtres

for loop execution error

2 vues (au cours des 30 derniers jours)
MUKESH KUMAR
MUKESH KUMAR le 6 Sep 2019
i had a for loop like this
for j=1:100
for i=1:48
F{j,1}(i,1)= some equations;
end
end
this is running well when j (1:100)>i(1:48) and not running for j<i values like if
for j=1:30
for i=1:48
F{j,1}(i,1)= some equations;
end
end
then its F cell having only 30 values for i=30th values . but I need 48 values when j=1:30 means F cell size should be {30,1} and each cell having (1*48) array.
and in another for loop,
for t=1:100
G(t)=trapz(X(t),Y(t));
end
if at G(55) its values can not calculated due to X(55) or Y(55) have no values/data sufficient for its operation then how can I execute this for loop without the error because I need the array untill the error come or not come G(55) is needful for me before the error and want to continue the program .

Réponse acceptée

Sebastian Körner
Sebastian Körner le 6 Sep 2019
For your second problem try:
for t=1:100
try
G(t)=trapz(X(t),Y(t));
catch
continue;
end
end
when the error occures at t=55 , you jump to the catch part and your loop continues with the next iterration
  2 commentaires
MUKESH KUMAR
MUKESH KUMAR le 6 Sep 2019
thanks for your helps it working well but then after execution the G vector values from 56 to 100 is zero and size of G is (100,1) but i want it till G(55,1) only
Sebastian Körner
Sebastian Körner le 6 Sep 2019
in this case simply replace the continue with break
for t=1:100
try
G(t)=trapz(X(t),Y(t));
catch
break;
end
end

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by