imcrop function problem for 16bit image 2019b
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Dear all,
The following imcrop code gives an error in 2019b
I = imread('XX.tif');
[Icrop, rect] = imcrop(I, [ ]);
It seems that 2019b does't support [ ] with imcrop. If you are working with 16 bit images then you will be in trouble because you need to see the image before croping it, and for that you need to put the [ ].
Any idea how to overcome this problem?
Thank you in advance.
Meshoo
6 commentaires
Walter Roberson
le 12 Oct 2019
Please name a particular release that documents using [] as a parameter to imcrop() . I looked through the archived documentation for several releases and could not find any evidence that it was ever a supported option.
Similarly, we need to use [ ] when croping uint16 image in order to dispaly the image before cropping it.
So display the image with imshow() with the documented [] option, and call imcrop() on the handle returned by imshow:
h = imshow(I, []);
[Icrop, rect] = imcrop(h);
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Walter Roberson
le 12 Oct 2019
h = imshow(I, []);
[Icrop, rect] = imcrop(h);
9 commentaires
Image Analyst
le 18 Oct 2019
Then you'll be making a lot of bug reports. There is a constant flow of functions either changing inputs, being deprecated, or being removed completely as versions progress through the years. I don't see how that, either filing bug reports or writing a custom wrapper and calling that from your code, is any better than just hitting the delete key 3 times.
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