How to compare two vectors on distance and isolate consecutive segments?

Hi,

I want to compare/melt two vectors that represent two data strains that are closely connected to each other:

A = [134	163	185	207	229	251	273	295	319	1277	1364	1760	1793	1823	1851	1880	1909	1939	1969	2003]; 
B = [144	172	194	216	238	260	282	305	327	1805	1835	1863	1892	1921	1950	1983];

What I want is that it creates a single vector that contains A and B together, so that it alternates. Here, the condition is that it has to alternate from A to B / B to A depending on the smaller number and that the difference between the alternating numbers can't be bigger 40. Also I want to know which numbers don't fit. So the output would be:

Output = [134 144 163 172 185 194 207 216 229 238 251 260 273 282 295 305 319 327 1793 1805 1823 1835 1851 1863 1880 1892 1909 1921 1939 1950 1969 1983 2003]
LeftOut = [1277 1364 1760]

Does anyone has a good suggestion how to solve this?

[David Hill]

Output=[];
LeftOut=[];
for i=1:length(A)
    if abs(A(i)-B(i))<=40
        Output=[Output,A(i),B(i)];
    else
        LeftOut=[LeftOut,A(i)];
    end
end

Answer 1

[Andrei Bobrov]

d = abs(A(:) - B(:)') <= 40;
loA = any(d,2);
loB = any(d,1);
output = zeros(nnz([loA(:);loB(:)]),1);
output(1:2:end) = A(loA);
output(2:2:end) = B(loB);
LeftOut = [A(~loA),B(~loB)];

[David Hill]

Good solution