I got this Error :Matrix dimensions must agree

Q1: When i input this formula ; f=(4/pi)*sum((1./n)*sin(2*pi*n.*t)) I got this error: Matrix dimensions must agree
Where n=1:2:401 and t=linspace(-0.5,0.5,250)
Q2: f=1/pi+0.5*sin(pi*tau)-2/pi*(cos(pi*n'*tau)/n'.^2-1) tau=linspace(-0.5,0.5,250); n=2:2:106; i get the same error !
Please correct it for me. And show me where are the mistakes

Réponses (3)

Andrei Bobrov
Andrei Bobrov le 18 Sep 2012
Modifié(e) : Andrei Bobrov le 18 Sep 2012
one way
%W1:
n = (1:2:401).';
t = linspace(-0.5,0.5,250);
f = 4/pi*sum(bsxfun(@times,1./n,sin(2*pi*n*t)));
%W2:
n = (2:2:106).';
tau = linspace(-0.5,0.5,250);
f = 1/pi+bsxfun(@minus,0.5*sin(pi*tau),2/pi*(bsxfun(@rdivide,cos(pi*n*tau),n.^2)-1));

2 commentaires

Andrei Bobrov
Andrei Bobrov le 18 Sep 2012
corrected
Jan
Jan le 18 Sep 2012
Mohammed has written [MOVED from answer to comment section]:
But i need 250 variables for t

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Jan
Jan le 18 Sep 2012
for the expression n .* t the variables n and t must have the same size. Perhaps you want a matrix like, e.g. created by a dyadic product:
n(:) * t
But as long as you do not specify this, n .* t is simply a bug, when the sizes differ or non of them is a scalar.
Mohammed
Mohammed le 18 Sep 2012

0 votes

Non of answers work !

1 commentaire

Jan
Jan le 18 Sep 2012
Modifié(e) : Jan le 18 Sep 2012
Please, Mohammed, do not post comments to answers as answer, but as comment. When you claim, that a suggested method "does not work", be so kind to show the code, the error message or an explanation of the difference between your expectation and the results.
Of course my suggestion will "not work", because I told you, that there is a bug in your code or that you at least did not tell us, what you want to achieve exactly enough. How could this be "working"?!

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le 18 Sep 2012

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