Computing determinant of matrix A using LU factorization

3 vues (au cours des 30 derniers jours)
Emily Gallagher
Emily Gallagher le 8 Oct 2019
Commenté : the cyclist le 8 Oct 2019
I must compute the determinant of an nxn matrix A using LU factorization. I have already calculated L and U in a different 'lufact' function. For some reason though, my funcion for computing the determinant of A, which is just equal to the product of the diagonal entries of matrix U is not working.
seed = 7;
rng(seed)
A = randn(n,n);
[L,U] = lufact(A);
function f = determ(A)
%Computing determinant of A
f = prod(diag(U));
end
  1 commentaire
the cyclist
the cyclist le 8 Oct 2019
One weirdness here. If your function definition is really
function f = determ(A)
%Computing determinant of A
f = prod(diag(U));
end
then that is going to throw an error, because you don't pass in U. So, maybe you are not really calculating with the inputs you expect?

Connectez-vous pour commenter.

Réponses (1)

the cyclist
the cyclist le 8 Oct 2019
Modifié(e) : the cyclist le 8 Oct 2019
If I use the lu function from MATLAB (instead of your lufact function), I get the expected result. So, I'd double-check your LU factorization code.
seed = 7;
n = 5;
rng(seed)
A = randn(n,n);
[L,U] = lu(A);
f = prod(diag(U))
d = det(A)
f =
-8.0745
d =
-8.0745

Catégories

En savoir plus sur Operating on Diagonal Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by