Given 2 red beads, 2 blue beads, 1 yellow bead, and 1 green bead, how many different necklaces can be made?

This is the code I have written, it is giving me an answer of 180, but the answer is supposed to be 16, what needs to be fixed?

% This script will calculate the number of possible arrangements for a

% necklace given a certain number of beads assuming circular shifts and

% flips are the same

%Create a vector with the beads where a number is assigned to each color

v=[1 1 2 2 3 4];

% 1=red

% 2=blue

% 3=yellow

% 4=green

% Determine total number of beads and all possible permutations

n=numel(v);

p=perms(v);

% Take into account colors with >1 beads

p2=unique(perms(v),'rows');

% Generate flips of all permutations

f=fliplr(p2);

% Generate circular shifts for all permutations

for i=0:n

c=circshift(p2,i);

end

% Combine the three matrices into one and remove duplicate rows

combined=[p2;f;c];

final=unique(combined,'rows');

configurations=size(final,1);

fprintf('The number of possible configurations is %d\n',configurations)

[Image Analyst]

How is this question different than what you posted here in this link?

[SammyJoe]

I have since updated the code I had with the circular shifts, and now I cannot find where the problem is

[Walter Roberson]

It would make more sense to put the updated code and discussion in that other question.