append new row in loop

hi all, i need some solution. Please help. I want to create a function which has L is a matrix 1:11 and return a matrix 40:11 after 40 times of loop.

For example: everytime this function being call, it will carry L and append in row

1st call : L [13 25 15 11 11 14 12 12 10 14 1]

2nd call L [13 25 15 11 11 14 12 12 10 14 2]

....

end result, this function will return:

[13 25 15 11 11 14 12 12 10 14 1]

[13 25 15 11 11 14 12 12 10 14 2]

...

TQIA

function [] = sortmatrix(L)

% append row in matrix

for c = 1:40

b =(L(1,:))

b = L(b; %not sure how to add b into matrix

end

kk = reshape(b,[],11);

%disp(kk)

end

Answer 1

[Bhaskar R]

Its a simple concatanation operation, pass the values e as

L is your constant matrix and number iof loops

as

L =  [13  25  15  11  11  14  12  12  10  14];
nLoops = 40;

Then execute your function

function result_mat = sortmatrix(L, nLoops)
% here nLoops is 40 times of loop and L is constant matrix
% E.g L =  [13  25  15  11  11  14  12  12  10  14] and nLoops = 40
result_mat = zeros(nLoops, size(L,2)+1);    % Initialize result matrix
for ii = 1:nLoops
    result_mat(ii,:) = [L, ii]; % concatante loop value to result matrix
end
end

The variable result_mat is your required matrix

[Khairul Nur]

the resulted matrix have the same value of totalk1 for 40 times which is wrong. I want the matrix to append updated value of totalk1.

here is my main:

for n = i:40

result1= sum((c1- MM(i,:)).^2)

result2= sum((c2- MM(i,:)).^2)

result3= sum((c3- MM(i,:)).^2)

result4= sum((c4- MM(i,:)).^2)

i=i+1

totalk1 = [result1,result2,result3,result4]

S=sort_euc(totalk1,40)

end

meanwhile sort_euc is the function as below:

function [sorted_euc] = sort_euc(totalk1,nLoops)

% here nLoops is 40 times of loop and L is constant matrix

% E.g L = [13 25 15 11 11 14 12 12 10 14] and nLoops = 40

sorted_euc = zeros(nLoops, size(totalk1,2)+1); % Initialize result matrix

for ii = 1:nLoops

sorted_euc(ii,:) = [totalk1,ii]; % concatante loop value to result matrix

end

end