Crop an image using coordinates
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Anonymous26
le 2 Nov 2019
Modifié(e) : Anonymous26
le 27 Nov 2019
I am getting a grid for an image using vertical projection.
I want to crop the image part, within the 2 of the points as one cropping image.
Can someone advice me on this?
Thanks!
4 commentaires
Réponse acceptée
Image Analyst
le 2 Nov 2019
I would use regionprops() to find the start and stop of each non-zero segment, then crop. Something like (untested)
props = regionprops(verticalProfile, 'PixelIdxList');
for k = 1 : length(props)
row1 = props(k).PixelIdxList(1, 1)
row2 = props(k).PixelIdxList(1, end)
croppedImage = grayImage(row1:row2, :)
imshow(croppedImage);
drawnow;
end
11 commentaires
Image Analyst
le 4 Nov 2019
It should only get to that line if it's an RGB image. What does this say?
ndims(grayImage)
whos grayImage
[rows, columns, numberOfColorChannels] = size(grayImage)
Don't use semicolons and look to see what it reports to the command window.
Plus de réponses (1)
darova
le 2 Nov 2019
Here is an attempt
clc,clear
I = imread('Capture.jpeg');
I1 = im2bw(I); % convert to binary
I2 = bwareaopen(~I1,100); % remove numbers (small areas)
[row,col] = find(I2);
I3 = I2*0;
h = 1; % crop thickness
ii = row(1)+h:row(end)-h;
jj = col(1)+h:col(end)-h;
I3(ii,jj) = I2(ii,jj); % crop
I4 = bwareaopen(I3,200); % remove small areas
[L,n] = bwlabel(I4); % label image
for i = 1:4
subplot(2,2,i)
I5 = L == i; % find part of a curve
I6 = imdilate(I5,ones(5)); % highlight the part
II = cat(3,~I6,I1,I1)*255;
imshow(II) % show original image and part of a curve
end
im assuming the original image has no those circles
2 commentaires
Voir également
Catégories
En savoir plus sur Image Processing Toolbox dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!