indexing a square matrix in the best possible way

I have a square matrix and I would check some condition of every element of it.which could be the best way to indexing a square matrix using for cycle?

[Ryan]

What condition are you looking to test? What type of points are you looking to index? For example if you have a matrix and want to find all the values greater or equal to 100 you could do:

 idx_100 = A >= 100;

More complex conditions may require alternative methods.

Answer 1

[Azzi Abdelmalek]

you can use cellfun for cell class or arrayfun and find for double class

[Salvatore Mazzarino]

but let's suppose I have a matrix A 2x2. I would check the condition of every element.If I had a vector I do:

for i = 1 : 10
  if vector(i) some condition
    do-something
  end
end

but with a matrix 2x2 how can I do?

[Azzi Abdelmalek]

A=[2 3;10 25]
% that depends on the the actions that will be taken
% for examle if you wan to find index of elements of A that are >5
[idxn,idxm]=find(A>5)

[Azzi Abdelmalek]

if you want to replace all value of A that are>=3 by 100 for example

 A(arrayfun(@(x) x>=3 ,A))=100

sometimes for loop can't be replaced

Answer 2

[Walter Roberson]

If you are using a nested for loop, have the inner loop be over the first index.

If you are using a single for loop, just use natural index order.

Answer 3

[Image Analyst]

Savatore, it depends on what you want to do. You need to tell us because that will affect the answer. For example if you have matrix A and matrix B and you want to set matrix B to 999 every place that matrix A is between 100 and 200, you'd do something like this

B(A>100 & A<200) = 999;

No for loop needed. In general, you do something like

logicalIndexes = (A == someCondition);
someMatrix(logicalIndexes) = someValue; % someMatrix could be A or some other matrix.

But if you wanted to do something like beep a tone the number of times that equals the value of A but only for all A that are less than 10, or something else that's more complicated, then you might want to use a loop.