# How to perform right circular shift

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sadiqa ilyas on 4 Nov 2019
Commented: sadiqa ilyas on 5 Nov 2019
Hi. I have written a code to perform circular shift but it does not give me all X28 and Y28 keys . It returns only one X28 and Y28 with out any circular shift.What I did wrong
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
icount=0;
for i=1:16
icount=icount+R_key(i);
I=icount;
end
%circular shift
X28 = circshift(x', -icount)';
Y28 = circshift(y', -icount)';

Shubham Gupta on 4 Nov 2019
what was the output that you were expecting?
Walter Roberson on 4 Nov 2019
sum(R_key) is 28, so icount is 28. That is the same as the length of your data, so you are circular shifting each bit of data exactly to the same place it started.
sadiqa ilyas on 4 Nov 2019
Yes but I want all these outputs. 16 out puts after the circular shift performed according to R_key

Walter Roberson on 4 Nov 2019
key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
shift_counts = cumsum(R_key);
num_shifts = length(shift_counts);
x_shifted = zeros(num_shifts, length(x));
y_shifted = zeros(num_shifts, length(y));
for i = 1 : num_shifts
x_shifted(i, :) = circshift(x, -shift_counts(i));
y_shifted(i, :) = circshift(y, -shift_counts(i));
end

#### 1 Comment

sadiqa ilyas on 5 Nov 2019
Thanks