I need to make distibution of 15 apples among 4 person [a b c d],
each person can have a value betwwen 0-15. and summation always (a+b+c+d=15)
so how can i generate the matrix for all possible combinantion
so i eapect matrix as
a = [1 14 0 0
0 0 0 15
3 6 2 4
...................
...................]

2 commentaires

Walter Roberson
Walter Roberson le 16 Nov 2019
One approach is to ndgrid() all possible combinations, and then check those to find the ones that add up to the right number.
Nasser Hakami
Nasser Hakami le 18 Nov 2019
thanks. however i couldn't manage to do it

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 Réponse acceptée

the cyclist
the cyclist le 16 Nov 2019

0 votes

I would download John D'Errico's partitions function, and then I believe your answer is
p = partitions(15,[1 1 1 1])

5 commentaires

Nasser Hakami
Nasser Hakami le 18 Nov 2019
tahnks. It look great code. but i coulnt mange to run correctly. i will try again to adapt it
the cyclist
the cyclist le 18 Nov 2019
Do you mean that the code will not work for you, or that you do not get the result you expect?
(FYI, Walter's solution and this one give the same result.)
Nasser Hakami
Nasser Hakami le 18 Nov 2019
Modifié(e) : the cyclist le 18 Nov 2019
first tahnks for your feedback
to answer you: i could not mange to run the code
i will try to make exampele easier
4 apples, 2 person. so ALL combinations are
[0 4
1 3
2 2
3 1
4 0]
if 4 apples , 3 persons. combination are
[0 0 4
0 1 3
0 2 2
0 3 1
0 4 0
1 0 3
1 1 2
1 2 1
1 3 0
2 0 2
2 1 1
2 2 0
3 0 1
3 1 0
4 0 0]
I don't think an easier example was needed, but I can verify that
partitions(4,[1 1 1])
gives the same answer (not necessarily in the same row order).
I'm not sure why you couldn't run the code. Did you do the following?
  • go to the link I uploaded
  • click on the download button to get the files
  • unzip the files
  • put the partitions.m file in your path so that you can run it
Nasser Hakami
Nasser Hakami le 19 Nov 2019
thanks a lot
it is working perfect
the problem that i just copied the code from webpage and i didnt download file

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 18 Nov 2019

0 votes

[Ag, Bg, Cg, Dg] = ndgrid(0:15);
Eg = [Ag(:), Bg(:), Cg(:), Dg(:)];
mask = sum(Eg,2) == 15;
selected = Eg(mask,:);
a = selected(:,1);
b = selected(:,2);
c = selected(:,3);
d = selected(:,4);

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