Mapping two binary bits to one

I have generate a set of bits 0 and 1,

N=10000;

m=(sign(randn(1,N))+1)/2;

The problem is how do I group the bits? For example

00=-j

01=-1

10=1

11=j

[Image Analyst]

No idea what you want, but look at dec2bin() and/or bin2dec().

Answer 1

[Walter Roberson]

vals = [-1j, -1, 1, 1j];

m2 = reshape(m, 2, []);
idx = m2(1,:) * 2 + m(2,:) + 1;
output = vals(idx);

[salad9996]

thanks

[salad9996]

Hi, from the complex symbols, any method that I can get back to orignal binary number which contain 0 and 1?

[Walter Roberson]

ismember to get an index. Use that as a row index into a 4x2 array.

[Walter Roberson]

[, idx] = ismember(Symbols, [-1j, -1, 1, 1j]);
bits = [0 0; 0 1; 1 0; 1 1] .';
bit_vector = reshape(bits(:, idx), 1, []);