structure indices in one line

1 vue (au cours des 30 derniers jours)
Robert
Robert le 1 Oct 2012
I would like to extract values from a structure. I know how to do it in two lines of code, but is it possible in one?
temp = urlAuthsMap.values;
temp{1}
My solution would have been something like [urlAuthsMap.values]{1} but that doesn't work.
>> temp = urlAuthsMap.values
Columns 1 through 11
{1x4 cell} {1x1 cell} {1x3 cell} ...
>> temp{1}
ans =
'S. A. Abraham' 'H. A. Bodner' 'C. G. Harrington' 'R. C. White Jr.'

Réponse acceptée

Matt Fig
Matt Fig le 1 Oct 2012
Modifié(e) : Matt Fig le 1 Oct 2012
V = values(urlAuthsMap,KH); % KH is the key you want. See key.
From the link you showed above .... ;-)
  1 commentaire
Robert
Robert le 19 Oct 2012
Thanks a lot for your answer by email. i'll paste it in below
As far as I know, there is no way to index into newMap the way you want to.
keySet = {'Jun','Jul','Aug'}; valueSet = [ 69.9, 32.3, 37.3]; newMap = containers.Map(keySet,valueSet); values(newMap,keySet(1)) % This is how to do it.
As far as your other example, try this:
a{1} = [1,2,3] a{2}=[4,5,6]
a{2}(1)

Connectez-vous pour commenter.

Plus de réponses (1)

Image Analyst
Image Analyst le 1 Oct 2012
Modifié(e) : Image Analyst le 1 Oct 2012
urlAuthsMap.values = {'S. A. Abraham', 'H. A. Bodner', 'C. G. Harrington', 'R. C. White Jr.'}
% Here's how to do it.
caName1 = urlAuthsMap.values(1) % This is a cell.
strName1 = urlAuthsMap.values{1} % This is a string.
  1 commentaire
Robert
Robert le 1 Oct 2012
Thanks, I've tried this but am getting errors for both. I realized that maybe my map object is special and doesn't work like a normal cell array. Any ideas?
urlAuthsMap.values{1} Error using containers.Map/values Invalid input for argument 2 (rhs2): Value must be 'cell'.
>> urlAuthsMap.values(1) Error using containers.Map/values Invalid input for argument 2 (rhs2): Value must be 'cell'.

Connectez-vous pour commenter.

Catégories

En savoir plus sur MATLAB dans Help Center et File Exchange

Tags

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by