good evening family I was calculating the autocorrelation of the function cos (wt) but every time I compile I get an error like Error using plot Vectors must be the same length.
Help me please.
this is my code :
function autocorrx
f0=20; N=1000 ;
k=5; Tmax=k/f0;
t=0/2:Tmax/N:Tmax;
x=cos(2*pi*f0*t);
subplot(1,1,1);
plot(t,x);
axis([0 0.1 -1 1]);grid;
xlabel('t(s)');
ylabel('cos(wt)');
C = xcorr(x,x)*Tmax;
subplot(2,2,2) ; plot(t,C) ;
axis([-0 0.1 -1 1]);
grid
xlabel ('t') ;
ylabel ('Cxx(t)') ;
title ('autocorrelation ')
end

5 commentaires

That error means that "Vectors must be the same length". It's pretty clear.
K>> size(t)
ans =
1 1001
K>> size(C)
ans =
1 2001
Clearly t and C and not the same length. So Matlab doesn't know how to pair those coordinates which is required for plotting.
thank you for your answer first the code has no more problem but I can not see autocorrelation of cos (wt) do you know why ???Capture.PNG
Because you're crushing the axis limits.
axis([-0 0.1 -1 1]);
Remove that line.
thank you sir sooooooooooooooooooooooooo much :0
Adam Danz
Adam Danz le 9 Déc 2019
Glad I could help!

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Adam Danz
Adam Danz le 9 Déc 2019
Modifié(e) : Adam Danz le 9 Déc 2019
The cross correlation function xcorr() will produce an output with 2*M-1 elements where M is the number of elements in the input. Perhaps you want to plot the results as a function of the lag.
[C,lags]= xcorr(x,x);
C = C*Tmax; % <--- this is from your code;
plot(lags,C);
Note that your subplots are not defined correctly. Assuming you want two vertically stacked subplot, the subplot definitions should be
subplot(2,1,1)
subplot(2,1,2)

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