Divide the matrix randomly, based on columns

5 vues (au cours des 30 derniers jours)
Joana le 11 Déc 2019
Commenté : Rik le 11 Déc 2019
Hi
I have a matrix x of size 78000x204. I need to divide it into nonoverlapping but random 70:15:15 percent of the data, based on number of columns.
Any help, how to do that.?
0 commentairesAfficher -2 commentaires plus anciensMasquer -2 commentaires plus anciens

Connectez-vous pour commenter.

Réponse acceptée

Rik le 11 Déc 2019
You mean like this?
fractions=[70 15 15];
x=rand(78000,100);%use 100 to show the split is indeed 75:15:15
groups=cell(size(fractions));%pre-allocate output
f=fractions/sum(fractions);
f=[0 cumsum(f)];
r=randperm(size(x,2))/size(x,2);
for n=1:numel(groups)
L= r>f(n) & r<=f(n+1);
groups{n}=x(:,L);
end
2 commentairesAfficher AucuneMasquer Aucune
Joana le 11 Déc 2019
Yes, but i'm not sure if it's dividing the data randomly and nonoverlapping.?
I can't figure it out as it's a long data with 78000x204.
Rik le 11 Déc 2019
Because randperm is generating the indices, this is guaranteed not to result in overlapping groups. Unless there are columns in your data that are equal to eachother, there is not be any match between the groups.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by