How do I get a symbolic differentiation of cfit/sfit functions?
16 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi everyone,
I am trying to get the symbolic partial derivative of a sfit function. Best case would be having the differentition as an sfit function, too.
Thanks in advance!
EDIT:
Here's an example:
%data
x = [0.5850;0.0734;0.8223;0.7229;0.9259;0.4926];
y = [0.6549;0.8901;0.5385;0.2822;0.9760;0.0364];
z = [0.3262;0.9730;0.3650;0.3091;0.1209;0.9158];
%surface fit
sf = fit([x, y],z,'poly22')
plot(sf)
% Linear model Poly22:
% sf(x,y) = p00 + p10*x + p01*y + p20*x^2 + p11*x*y + p02*y^2
% Coefficients:
% p00 = 5.048
% p10 = -11.04
% p01 = -1.326
% p20 = 5.179
% p11 = 5.682
% p02 = -3.135
Now I could use the differentiate method to get the derivative at specific points but I would like to have the derived function, like this (witthout having to derive it manually):
% sf_x(x,y) = p10 + 2*p20*x + p11*y
3 commentaires
Réponse acceptée
Walter Roberson
le 16 Déc 2019
When sf is the fit object,
f = subs(str2sym(formula(sf)),coeffnames(sf),num2cell(coeffvalues(sf).'));
vars = sym(indepnames(sf));
diff(f, vars(1))
5 commentaires
Walter Roberson
le 20 Déc 2019
The upper and lower bounds are in the fit options, which I have it add in via 'options', fitoptions(sf)
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Formula Manipulation and Simplification dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!