Subscript Error Plz help

1 vue (au cours des 30 derniers jours)
Fred
Fred le 3 Oct 2012
Pk is a 1*5 , and LandaMean is 1*37 matrice
b=1
m=6
for k=1:(n-(2*b)-m+1);
Pk = LandaMean(k+1:k+m-1);
for i=k+1:k+m-1
if sum(abs(Pk(i)-LandaMean(k)))<= (2*s);
LandaU =(1/m)*sum(LandaMean(k:k+m-1));
break
else
end
end
end
But I get this error:
Subscript indices must either be real positive integers or logicals.
Error in TailDep (line 50)
if sum(abs(Pk(i)-LandaMean(k)))<= (2*s);
Thank you
  1 commentaire
Fred
Fred le 4 Oct 2012
Thank you, I realized that I had used sum in other lines as a parameter so it was the making problem :)

Connectez-vous pour commenter.

Réponse acceptée

Razvan
Razvan le 3 Oct 2012
Just look at line 50 and what vectors are there. Probably there is something like
vector(negative_number)
So check why the index is negative...
  1 commentaire
Fred
Fred le 3 Oct 2012
Thank you

Connectez-vous pour commenter.

Plus de réponses (1)

Image Analyst
Image Analyst le 3 Oct 2012
Modifié(e) : Image Analyst le 3 Oct 2012
What is n and s? Whatever they are, they make either i or k negative or zero.
I guessed for n and s and ran this code and had no error whatsoever:
Pk = rand(1, 5);
LandaMean = rand(1, 37);
b=1;
m=6
n = 9 % Total guess
s = 10 % Total guess
for k=1:(n-(2*b)-m+1);
Pk = LandaMean(k+1:k+m-1);
for i=k+1:k+m-1
if sum(abs(Pk(i)-LandaMean(k)))<= (2*s);
LandaU =(1/m)*sum(LandaMean(k:k+m-1));
break;
else
end
end
end
Do you know how to step through code with the debugger to inspect variables?
  3 commentaires
Fred
Fred le 3 Oct 2012
Actually I found where is the problem but I don't know what should I do? the inside of sum becomes around 0.15 and it assumes that 0.15 is an index for sum!! but sum is a function here!
Walter Roberson
Walter Roberson le 3 Oct 2012
Are you sure that you did not accidentally create a variable with the name "sum" ? Check with
whos sum

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by