Please help me to code below problem

5 vues (au cours des 30 derniers jours)
sanjeeb
sanjeeb le 1 Jan 2020
Please help me to code attache problem

Réponses (2)

P K
P K le 1 Jan 2020
Modifié(e) : P K le 1 Jan 2020
@Sanjeeb... Instead asking someone to write the programme, you should ask the problem you are facing.
  1 commentaire
John D'Errico
John D'Errico le 1 Jan 2020
Modifié(e) : John D'Errico le 1 Jan 2020
The problem they are faciong is how to get through a course, without making the effort to really learn what is needed. What has been posted is a direct homework assignment. They do not really need to compute sin(x), because if they did, they would already find the sin function in MATLAB (or in almost any programming language, spreadsheet, or even many calculators.)
The assignment is itself fairly clear. It gives them the exact formula. It tells them to use a loop to compute said formula, and when to stop the loop.

Connectez-vous pour commenter.


Image Analyst
Image Analyst le 1 Jan 2020
Here's a snippet that will be useful to you:
% Ask user for one integer number.
defaultValue = 45;
titleBar = 'Enter an integer value';
userPrompt = 'Enter the integer';
caUserInput = inputdlg(userPrompt, titleBar, 1, {num2str(defaultValue)});
if isempty(caUserInput),return,end % Bail out if they clicked Cancel.
% Round to nearest integer in case they entered a floating point number.
integerValue = round(str2double(cell2mat(caUserInput)));
% Check for a valid integer.
if isnan(integerValue)
% They didn't enter a number.
% They clicked Cancel, or entered a character, symbols, or something else not allowed.
integerValue = defaultValue;
message = sprintf('I said it had to be an integer.\nTry replacing the user.\nI will use %d and continue.', integerValue);
uiwait(warndlg(message));
end
Here is another snippet:
>> denom = 1:6
denom =
1 2 3 4 5 6
Also check out the factorial() function.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits


Version

R2015a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by