# summation with for loop for all rows in another column

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MUKESH KUMAR le 13 Jan 2020
Modifié(e) : Raj le 13 Jan 2020
I had following data as attached
h = 1;
I_all size(3154*20)
So hmax = 20;
I1 = I_all(1,1) for first row and I1=I_all(2,1) for 2nd row and so on........
Need F_HL for all 3154 rows..........
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Rik le 13 Jan 2020
What have you tried so far? Especially the version with a for loop seems easy to implement.
MUKESH KUMAR le 13 Jan 2020
h=1:20;
F_HL_N = 0;
for i=1:20
F_HL_N = F_HL_N+(I_all(1,i)/I_all(1,1))^2* h(i)^2;
end
F_HL_D = 0;
for i=1:20
F_HL_D=F_HL_D+(I_all(1,i)/I_all(1,1))^2;
end
F_HL = F_HL_N/F_HL_D; % for first row
% now want to do for all 3154 rows in for loop

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### Réponses (1)

Raj le 13 Jan 2020
Modifié(e) : Raj le 13 Jan 2020
You are almost there. Put the whole thing in another loop that runs accross all the rows and store F_HL for each row like this:
for ii=1:3154
h=1:20;
F_HL_N = 0;
for i=1:20
F_HL_N = F_HL_N+(I_all(1,i)/I_all(1,1))^2* h(i)^2;
end
F_HL_D = 0;
for i=1:20
F_HL_D=F_HL_D+(I_all(1,i)/I_all(1,1))^2;
end
F_HL(ii) = F_HL_N/F_HL_D; % for iith row
end
Done!
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