Changing a Function to Accept vector inputs?

Hello, I am having trouble making my function run with vector inputs, I am assuming that this is because of the "if" and "elseif" statements that are included in the function, and I was just wondering how I could adjust my function to accomodate for vector inputs. The code is shown below.

function y = FcnEval(x)
 > if x < -2;
      >y = 1./((x.^2) + 1);
 > elseif (-2<=x) & (x<-1);
      y = sin(x);
 > elseif (-1<=x) & (x<1);
      y = x^2;
 > elseif (1<=x) & (x<2);
      y =2; 
 > else x>2;
      y = 1./(x+1);
  end

Answer 1

[Andrei Bobrov]

function y = FcnEval(x)
y = zeros(size(x));
for ii = 1:numel(x)
    if x(ii) < -2;
        y(ii) = 1./((x(ii).^2) + 1);
    elseif -2 <= x(ii) && x(ii) < -1;
        y(ii) = sin(x(ii));
    elseif -1 <= x(ii) && x(ii) < 1;
        y(ii) = x(ii)^2;
    elseif 1 <= x(ii) && x(ii) < 2;
        y(ii) = 2; 
    else
        y(ii) = 1./(x(ii)+1);
    end
end

or

y = zeros(size(x));
t1 = x < -2;
y(t1) = 1./(x(t1).^2 + 1);
t2 = -2 <= x & x < -1;
y(t2) = sin(x(t2));
t3 = -1 <= x & x < 1;
y(t3) = x(t3).^2;
y(1 <= x & x < 2) = 2;
t4 = x >= 2;
y(t4) = 1./(x(t4)+1);

or

f = {@(x)1./(x.^2 + 1);@sin;@(x)x.^2;@(x)2;@(x)1./(x+1)};
[b,b]=histc(x,[-inf;-2;-1;1;2;inf]);
y = arrayfun(@(ii,jj)f{ii}(jj),b,x);