Question on using interpolate function

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Deepa Maheshvare
Deepa Maheshvare le 28 Jan 2020
I've the following
x = [1 2 3 4 5 6];
data = [0.1 0.2 0.3 0.4 0.4 0.4];
vq1 = interp1(data,x,0.4)
I want to find the x value at which data has 0.4 (first occurence).
I used interpolate. But the following error occurS
The grid vectors must contain unique points.
Any suggestions on how to proceed when data doesn't contain uniqe values will be helpful
  1 commentaire
Deepa Maheshvare
Deepa Maheshvare le 28 Jan 2020
I'm still expecting answers for this post. Unfortunately, the following suggestions didn't help.

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Réponses (2)

KSSV
KSSV le 28 Jan 2020
Use logical indexing:
x = [1 2 3 4 5 6];
data = [0.1 0.2 0.3 0.4 0.4 0.4];
vq1 = x(abs(data-0.4)<10^-5)
  1 commentaire
Deepa Maheshvare
Deepa Maheshvare le 28 Jan 2020
Modifié(e) : Deepa Maheshvare le 28 Jan 2020
I'm looking for an interpolation function. It may happen that Ive to check for a value of 0.45 that is not present in data

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Bhaskar R
Bhaskar R le 28 Jan 2020
"I want to find the x value at which data has 0.4 (first occurence)."
match_loc = find(data == 0.4);
val = x(x == match_loc(1)); % first occurance of 0.4
  1 commentaire
Deepa Maheshvare
Deepa Maheshvare le 28 Jan 2020
What if I have to check for 0.45?

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