How to write code to plot graph of for this function
Afficher commentaires plus anciens
I wanted to know how to plot my a graph for my function. The x-axis needs to be values of 'v' from from 1-10. The y-axis is the values of the function y(v). I want to label the x-axis: v [mol/m^3] and y-axis y(v). How would I write the code for this? Below is the some of the code I have written.
P=2020000;%P,R,a,b are all constants
R=8.314;
a=0.16330;
b=0.00002401;
v=[0:1:10];%range of v values for the x-axis
y=((R*T)/(v-b))+((a)/((v^2+(2*b*v)-b^2)))+P
plot(v,y)
Réponses (3)
Sivakumar Selvam
le 4 Fév 2020
P=2020000;%P,R,a,b are all constants
R=8.314;
a=0.16330;
b=0.00002401;
v=[0:1:10];%range of v values for the x-axis
y=((R*T)/(v-b))+((a)/((v^2+(2*b*v)-b^2)))+P
plot(v,y);
xlabel('v [mol/m^3]')
ylabel('y(v)')
1 commentaire
Rafae Ahmed
le 4 Fév 2020
Prashanth Darla
le 4 Fév 2020
Modifié(e) : Prashanth Darla
le 4 Fév 2020
0 votes
Hey,you're all good if you declare T and elemenmtwise operatorfor division and power (Here I used T as 1)
Here's the code I suggest for you
P=2020000;%P,R,a,b are all constants
R=8.314;
a=0.16330;
b=0.00002401;
T=1;
v=(1:1:10);
disp(v);
for i =v
%range of v values for the x-axis
y=(((R*T)./(i-b))+((a)./((i.^2+(2*b*i)-b.^2)))+P);
disp(y);
end
plot(v,y);
xlabel('v [mol/m^3]')
ylabel('y(v)')
Hope this solves the issue.
1 commentaire
Rafae Ahmed
le 4 Fév 2020
Tomás Cardadeiro
le 17 Nov 2021
0 votes
Hi i know its just a little too late but see if thats not you want
clc
clear all
P=2020000;%P,R,a,b are all constants
R=8.314;
a=0.16330;
b=0.00002401;
T=1;
y1=[];
v1=[];
for v=0:10%range of v values for the x-axis
y=((R*T)/(v-b))+((a)/((v^2+(2*b*v)-b^2)))+P;
y1=[y1 y];
v1=[v1 v]
end
plot(v1,y1)
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