Effacer les filtres
Effacer les filtres

I have a map of different colors, I need all z values from greater than 0 to be red, all zero values to be white, and all below zero values to be blue

5 vues (au cours des 30 derniers jours)
color specifications
imagesc(z)
cmap = [1 0 0 ; 0 1 0 ; 0 0 1] ;
colorbar
colormap(cmap)
I applied the code above, but it just seperated the ranges equaly.

Réponse acceptée

Walter Roberson
Walter Roberson le 12 Fév 2020
Zz = (z>0) - (z<0);
imagessc(Zz)
colormap(cmap)
caxis([-1,1])
The caxis is there for protection in case z does not have a mix of negative and positive values.
If there can be nan in z then
Zz(isnan(z)) = nan;

Plus de réponses (1)

Shivaraj Durairaj
Shivaraj Durairaj le 12 Fév 2020
You can specify the clims argument to the imagesc function.
The values in z that are less than or equal to cmin (-1) map to the first color in the colormap. Values greater than or equal to cmax (1) map to the last color in the colormap. Values between cmin and cmax linearly map to the colormap.
For example,
z = randi([-10,10],[4,4]);
imagesc(z,[-1,1]) % clims = [cmin cmax]
cmap = [0 0 1;1 1 1;1 0 0]; %[blue;white;red]
colormap(cmap)
colorbar
Note: The above implementation works well when elements of z are integers. In case of non-integers, you may consider to limit the values of the elements to -1,0,1 after initializing z.
z(z<0) = -1;
z(z>0) = 1;
z(z==0) = 0;

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