Matrix Dimensions Must Agree

i got error in my code,,
it says Error using ==> / . Matrix Dimensions Must Agree
this is my code
a= input ('The number of participant :');
for c=1:a
str1 = ['Input Your Name :'];
str2 = ['Input Your First Score :'];
str3 = ['Input Your Second Score :'];
str4 = ['Input Your Third score :'];
b{c,1} = input(str1,'s');
b{c,2} = input(str2);
b{c,3} = input(str3);
b{c,4} = input(str4);
end
disp(b)
[m,n]= size (b);
Mb=max([b{:,2}])
fooCell = num2cell(NM);
for i=1:c
for j=1:3
R{i,j}=Mb{:,j}/b{i,j};
end
end
That error pointing at "/" in R{i,j}=Mb{:,j}/b{i,j};
anybody knows what's my fault?
please help me :)

Réponses (2)

Azzi Abdelmalek
Azzi Abdelmalek le 17 Oct 2012
Modifié(e) : Azzi Abdelmalek le 17 Oct 2012

0 votes

R{i,j}=Mb{:,j}/b{i,j};
what is Mb{:,j}?
and why Mb=max([b{:,2}])?

2 commentaires

baby
baby le 17 Oct 2012
Mb is for decide the highest value in matrix "b"
anyway, is that wrong?
no it is not, the highest is
bb=cellfun(@double,b(:,2:end))
Mb=max(bb(:))
Walter Roberson
Walter Roberson le 17 Oct 2012

0 votes

b{1,1} is a string, so you are trying to divide a matrix by a character vector.
By the way, have a look at the documentation for rdivide and compare it to the documentation for mrdivide

Cette question est clôturée.

Question posée :

le 17 Oct 2012

Clôturé :

le 20 Août 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by