hello everyone
i have a problem with the function sinc (i'm not so expert i started to use mathlab 3 months ago) and i wrote this:
x = 0:pi/100:2*pi;
y=sinc(x);
but i have an error:
Undefined function 'sinc' for input arguments of type 'double'.
someone can help me? thanks

 Réponse acceptée

Birdman
Birdman le 27 Mar 2020
Modifié(e) : Birdman le 27 Mar 2020

2 votes

Adapt its formula as follows:
x = 0:pi/100:2*pi;
y=sin(pi*x)./(pi*x);%sinc function
plot(y)

7 commentaires

Jack
Jack le 27 Mar 2020
It's also perhaps worth stating that some people (e.g. physicists) define as opposed to (which is more commonly used in the signal processing community).
Birdman
Birdman le 27 Mar 2020
The OP can adapt the formula according to the need I guess. My aim was to give the idea on implementation.
dert sgt
dert sgt le 27 Mar 2020
Modifié(e) : dert sgt le 27 Mar 2020
thanks to everyone so it's imposible to use sinc(x)? because it's easier for example or something similar
dert sgt
dert sgt le 27 Mar 2020
yes jack someone uses
Birdman
Birdman le 27 Mar 2020
Actually you should be able to use sinc(x) function but I guess you do not have signal processing toolbox or symbolic math toolbox which is required to use sinc(x). So, we have implemented the function according to its formula.
x = 0:pi/100:2*pi;
y=sin(pi*x)./(pi*x);%sinc function
plot(y)
or
x = 0:pi/100:2*pi;
y=sin(x)./x;%sinc function
plot(y)
Jack
Jack le 27 Mar 2020
While the singal processing toolbox has sinc() defined explicitly, you can always create a function that does this -- e.g. put the following in a file called sinc.m somewhere in your current path (or in ~/Documents/MATLAB/ or My Documents\MATLAB\)
function out = sinc(x)
% Deal with the removable singularity at 0 explicitly.
out = sin(x)./x;
out(x == 0) = 1;
end
dert sgt
dert sgt le 27 Mar 2020
thanks so much again you're fantastic!

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