How do you detect duplicate values within a random array?

Write a program to find if a vector of random generated integers contains any duplicate element. Return true if any value appears at least twice in the said vector and return false if every element is distinct.

I simply have no idea how to implement this. I believe this problem requires a for loop and a series of if statements.

Answer 1

[KSSV]

If you want to use inbuilt functions......you can use unique. Read about it. Let A be your array.

B = unique(A) ; 
if length(A)==length(B)
    fprintf('No elements repeated')
else
    fprintf('Elements repeated') 
end

[Aaron Zambiasi]

Thank you so much for the timely response!

[Aaron Zambiasi]

So it looks like your code says if the lengths of array A and array B are equal, then display 'No elements repeated'. But since B utilizes A to create a unique array, the lengths of A and B will always be equal, so 'No elements repeated' will always be displayed.

I'm looking for a code that (during the use of a random array) detects if there exist any duplicate random integers generated within that array.

[KSSV]

Read about loops..you can use two fo rloops and comapre the elements to see, if any element is repeating.

[Image Analyst]

Aaron, not true. The lengths are different if there are repeats because unique() throws out the repeats and sorts the values. Just look

A = [1, 2, 3, 4]
B = unique(A)
fprintf('length(A) = %d.  length(B) = %d.\n', length(A), length(B));
A = [1, 2, 2, 2, 9, 5]
B = unique(A)
fprintf('length(A) = %d.  length(B) = %d.\n', length(A), length(B));

A =

1 2 3 4

B =

1 2 3 4

length(A) = 4. length(B) = 4.

A =

1 2 2 2 9 5

B =

1 2 5 9

length(A) = 6. length(B) = 4.

[Aaron Zambiasi]

Oh! That makes so much more sense. Thank you both so much! I apologize for my lack of understanding originally. I am still super new at this program.