why the plotted function implicit doesn't have continuous surface?
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the attached pciture is a rotated cylinder which is plotted with fimplicit3 command in the interval 0 1500
the problem is I dont know why the surface of cylinder is not continuous? I checked the shape in another software that plot it continously but in matlab I have some problem.
in another screen shot you see if I changed the constant of function the plot would be continuous
here is the command i used for the plot with problem:
f = @(x,y,z) (z-x).^2+(x-y).^2+(y-z).^2-1000000;
>> interval=[0 1500];
>> fimplicit3(f,interval)


2 commentaires
David Goodmanson
le 8 Avr 2020
Hi sahand, whatever else is going on, if you do the 1e6 case with an interval of [0 1500] up to [700 1500] in steps of 100, you at least get some nice patterns.
sahand shams eshaghi
le 8 Avr 2020
Réponse acceptée
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sahand shams eshaghi
le 8 Avr 2020
0 votes
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