Struct to numeric variable
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Hi,
Sorry but this is a really simple question. I have a struct (3 fields and 446 elements) and I'm trying to access a a specific field and assign it to a workspace variable. I used the following syntax:
new_var = structname.fieldname
However, when I do this, I just get the first row of data in my field name. I want all the rows in structname.fieldname to be assigned to new_var.
When I try structname(1).fieldname or structname(2).fieldname - i get the corresponding row data only. I've tried the following: structname.fieldname(:,1) but get the following error message:
Expected one output from a curly brace or dot indexing expression, but there were 446 results.
Also tried structname(:).fieldname but again, just get the first row of data in fieldname - I'd like all 446 elements.
I know this is very simple but I just can't figure it out!
1 commentaire
Réponse acceptée
Stephen23
le 9 Avr 2020
Modifié(e) : Stephen23
le 9 Avr 2020
Apparently you have a 446x1 or 1x446 structure array, where the field in question contains a row vector. To concatenate all of the row vectors for that field you can use a comma-separated list:
new_var = vertcat(structname.fieldname)
Read how it works:
"Basically structname.AccRang extracted to be a variable..."
What you explain is consistent with a non-scalar structure where one field contains row vectors. So before being "extracted" to some variable, those row vectors need to be concatenated togther (they are NOT stored all as one matrix within the non-scalar structure), just like you would concatenate together any other set of row vectors to create one matrix.
Plus de réponses (3)
J. Alex Lee
le 8 Avr 2020
At the risk of having misunderstood:
new_var = [structname.fieldname]
This would work if you structname is a structure array 446 elements with each element containing the same 3 fields.
2 commentaires
J. Alex Lee
le 9 Avr 2020
If the variable "fieldname" is an array with consistent dimensions, try
new_var = vertcat(structname.fieldname)
Note that you want to be careful about vertcat or horzcat depending on what you want and the dimensions of the array in fieldname.
My first solution and Sindar's solution assumes horzcat.
J. Alex Lee
le 9 Avr 2020
Modifié(e) : J. Alex Lee
le 9 Avr 2020
Same as Stephen's answer below. By the way, if it is useful for you to keep the access-by-name, it may be easier to convert the struct array into a table type
t = struct2table(structname)
And you would get the array you intend in new_var by
t.AccRng
Sindar
le 8 Avr 2020
Modifié(e) : Sindar
le 8 Avr 2020
It sounds like you have a 446x1 structure array with 3 fields (each scalar?). Try this:
new_var = [structname.fieldname];
To understand why
new_var = structname.fieldname
wasn't working, look at the output of
structname.fieldname
It is probably something like:
ans=1
ans=6
ans=100
ans=4.6
...
Then, only the (I think) last one will be assigned to new_var. I'm not sure if it assigns each in turn or skips to the end, or only assigns the first.
You don't have rows of data, you have 446 separate containers that happen to share similar data
1 commentaire
Stephen23
le 9 Avr 2020
Modifié(e) : Stephen23
le 9 Avr 2020
"Then, only the (I think) last one will be assigned to new_var. I'm not sure if it assigns each in turn or skips to the end, or only assigns the first."
Only the first one will be assigned to the output variable, for the reasons given here:
Impala
le 9 Avr 2020
3 commentaires
J. Alex Lee
le 9 Avr 2020
answer in comment to my original answer - do not "answer" your own question, but rather comment on the provided answers.
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