Why is this wrong??

Hello :) I'm trying to draw the plots for E=a*c when j = 1 and E = a*b when j assumes other values, all in the same figure. The program just draws the first one, for E=a*c, and I cant understand why because it computes all different E for all the j (computes but does not do the plot). Can you tell me what I'm doing wrong? Your help will be very appreciated! Thanks in advance!
hold on
for j = 1:i
tau = (12*v*t(j)*Myr)/ro^2;
I = besseli(0.25,2*x./tau);
a = (md/(2*pi*ro));
b = (tau^-1).*(x.^-1/4).*I.*exp(-(1+x.^2)/tau);
c = normpdf(x,1,0.05);
if j == 1
E = a.*c;
else
E = a.*b
end
plot(x, E.*(1/a), colors(j))
end
hold off

3 commentaires

Matt J
Matt J le 24 Oct 2012
Modifié(e) : Matt J le 24 Oct 2012
The posted code doesn't run, since you haven't defined 'i' for us, and other variables as well.
Iris
Iris le 24 Oct 2012
Ms = 1.98919e33;
Rs = 6.9599e10;
Myr = 3.15569e13;
v = 1e5;
md = 0.01*Ms;
ro = 2*Rs;
x = [0:0.016:16]
t = [0:2e12:1e13];
i = length(t);
colors = ['r' 'b' 'g' 'b' 'g' 'b' ];
for j = 1:i
tau = (12*v*t(j)*Myr)/ro^2;
I = besseli(0.25,2*x./tau);
a = (md/(2*pi*ro));
b = (tau^-1).*(x.^-1/4).*I.*exp(-(1+x.^2)/tau);
c = normpdf(x,1,0.05);
if j == 1
E = a.*c;
else
E = a.*b
end
hold on
plot(x, E.*(1/a), colors(j))
end
hold off
end
Christoph
Christoph le 24 Oct 2012
Weird since it works for me (R2008a, V7.6.0). Have you checked the output using subplot(2,3,j) at the start of the loop? since the value of E peaks at "8" in the 1st and <10^-12 in the other plots, so all together they appear as line... Otherwise, which Matlab release do you use?

Réponses (2)

Matt Fig
Matt Fig le 24 Oct 2012
Modifié(e) : Matt Fig le 24 Oct 2012

0 votes

I run your code and it plots 6 lines. check for yourself:
>> length(findobj('type','line'))
ans =
6
I think maybe you are not noticing because some lines overlap. Have a look:
ylim([0 1e-12])
Matt J
Matt J le 24 Oct 2012

0 votes

Might be useful to change this
hold on
plot(x, E.*(1/a), colors(j))
to this
semilogy(x, E.*(1/a), colors(j));
hold on

Cette question est clôturée.

Question posée :

le 24 Oct 2012

Clôturé :

le 20 Août 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by