Find runs of repeated ones of any length and put into a cell array to compare indices

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Teddy Fisher
Teddy Fisher on 17 Apr 2020
Commented: Teddy Fisher on 21 Apr 2020
Hello,
I have two logical arrays, A & B, of size 370x23. They are the ouputs from two different functions performed on the same matrix, C.
A contains long runs of 1s while B contains 1-5 (approx) 1s in a row at a time.
I want to find strings of 1s (or rund of consecutive 1s) of any length in A to check if their indices overlap at all with B. If the strings in A contain B, then I want to keep the entire string of 1s in A. If they don't, then the whole string goes to 0s.
Another way to ask this would be how to group strings of 1s and then use their indices to check overlap with another set of indices.
Thanks youse.

Answers (1)

Sahithi Kanumarlapudi
Sahithi Kanumarlapudi on 20 Apr 2020
Hi,
You could use the 'find' function to find the indices at which the 1's are present and compare those indices.
For more information on how to use find function refer to the following link
  4 Comments
Teddy Fisher
Teddy Fisher on 21 Apr 2020
I looked up the documentation for regionprops and I don't see how that would be done. Any advice?

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