how to convert pressure versus time to pressure versus frequency using fft function
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I have tried to convert pressure versus time data to pressure versus frequency using FFT function
This is the pressure versus time signal

after using fft
deltaT=2.5e-6;
fs=1/deltaT;
pxx0 = fft(p);
n = length(p); % number of samples
f = (0:n-1)*(fs/n); % frequency range
mag=abs(pxx0);
figure(1)
semilogx(f,mag)
ylabel ('magnitude');
xlabel ('frequency');
This is the output of FFT function

How to convert the magnitude of FFT to corresponding pressure value like this graph ? in form of pressure versus frequency

Accepted Answer
Mehmed Saad
on 23 Apr 2020
Edited: Mehmed Saad
on 23 Apr 2020
- set xlim between 30 and 1e6
- set you xtick as [30 300 3e3 3e4 3e5]
- turn off xMinorTick
- turn off xMinorGrid
- turn on grid
- change linewidth to 1.5
Although it looks like window is also applied on the pressure data and fft size is also greater than the size of signal (next2pow is used)
8 Comments
Mehmed Saad
on 23 Apr 2020
Edited: Mehmed Saad
on 23 Apr 2020
fs = 1000;
t = 0:1/fs:1-1/fs;
s = exp(2j*pi*10*t);
L = length(s);
n = 2^nextpow2(L);
Y = fft(s,n);
Pp = abs(Y)/L;

figure,plot(Pp)
s = real(s);
Y = fft(s,n);
Pp = abs(Y)/L;
figure,plot(Pp)

Pp = abs(Y)/L*2; % because we take fft of real componnet only
figure,plot(Pp)

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