Hi my english is not good but i will try.
i need create the next signal:
m2(t)=u(t+1)+6*u(t-3)-10*u(t-6)
u(t):impluse of amplitude equal 1
how i cant do it?
well after i need modulate... but i dont need help in that.
thx :)

3 commentaires

Azzi Abdelmalek
Azzi Abdelmalek le 28 Oct 2012
what about the width of your pulse, or are you working with discret time?
Felipe Farias
Felipe Farias le 29 Oct 2012
well i use a widht very small... but in discrete time would be better.
PD: thx for function
Azzi Abdelmalek
Azzi Abdelmalek le 29 Oct 2012
if the pulse had a width(even with eps width) that means it's continuous. Check my answer, you can set the width and the amplitude

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Azzi Abdelmalek
Azzi Abdelmalek le 28 Oct 2012
Modifié(e) : Azzi Abdelmalek le 28 Oct 2012

0 votes

save this function
function p= puls(w,A,t)
% w:pulse width
% A:pulse amplitude
% t:time vector
n=length(t);
p=zeros(1,n);
idx=find(abs(t)<=w/2)
p(idx)=A
then call in your m file call the function
w=4 % the width of your pulse
A=1 % the Amplitude of your pulse
t=-10:0.01:10; % time vector
m2=puls(w,A,t+1)+6*puls(w,A,t-3)-10*puls(w,A,t-6)

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Wayne King
Wayne King le 28 Oct 2012

0 votes

Your signal is just a superposition (sum) of shifted unit step sequences.
For t = -1,0,1,2 m2(t) = 1
For t = 3,4,5 m2(t) = 7
For t = 6,7,8,9,...
m2(t) = -3
u1 = ones(100,1);
u2 = [zeros(4,1); 6*ones(96,1)];
u3 = [zeros(7,1); -10*ones(93,1)];
m2 = u1+u2+u3;
n = -1:98;
stem(n,m2,'markerfacecolor','b')

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