How do I draw barh using both axes values?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
farzad
le 27 Avr 2020
Commenté : Walter Roberson
le 28 Avr 2020
Hi All
How do I draw barh ( horizontal bars) taking into consideration both axes values : saying when 0<x<100 , draw a bar between 10<y<12
1 commentaire
Réponse acceptée
Walter Roberson
le 28 Avr 2020
x_to_draw_at = x(0 < x & x < 100);
bar(x_to_draw_at, 12*ones(1,length(x_to_draw_at)), 'basevalue', 10)
4 commentaires
Walter Roberson
le 28 Avr 2020
For values of ranges, by definition ranges <= max(ranges). When ranges is entirely positive, then max(ranges) is positive and max(ranges)*1.1 is even larger than max(ranges) so you can be sure that ranges < max(ranges)*1.1 .
So when could ranges < max(ranges)*1.1 be false?
- max(ranges) is 0, in which case 0*1.1 is 0, and 0 < 0 is false. On the other hand, the case of 0 is already eliminated by 0 < ranges
- max(ranges) is negative, in which case max(ranges)*1.1 is more negative, and it could be the case that there are some values that are more negative than max(ranges) but not as negative as max(ranges)*1.1. For example, -10.5 and -10, max() is -10, max()*1.1 is -11, and -10.5 < -11 is false. However, this can only happen for negative values, never for positive values, and you already eliminate negative values with 0 < ranges .
You should reconsider your test. Perhaps you want something like max(ranges)*0.9
by the way , the bars should be horizontal. does the code do this ?
You are going to need to describe what the output should look like: we as outsiders need to assume that the x values are not sorted and not continuous.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Lighting, Transparency, and Shading dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!