48 Dimensional Euclidean Distance.
11 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi Guys, Hopefully this will be a quicky. If I have two points in two dimensional space I find the distance as:
sqrt((x1-x2)^2 + (y1-y2)^2)
This is all good and well, but if I want the distance when each point has 48 (or otherwise) coordinates I don't really want to type out that equation. So is there some MatLab function which will let me pass it two arrays and find the resultant distance?
Thanks in advance,
Tim.
Réponse acceptée
Jan
le 8 Nov 2012
Modifié(e) : Jan
le 8 Nov 2012
Most of all the components should not be stored in x1, y1, z1, ... but is vectors x1=[1 x 48], x2=[1 x48]. Then some alternatives:
x1 = rand(1, 48);
x2 = rand(1, 48);
x12 = x2 - x1;
Dist1 = sqrt(sum(x12 .^ 2))
Dist2 = sqrt(x12 * x12.') % DOT product calculates the sum internally
Dist3 = norm(x12)
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Statistics and Machine Learning Toolbox dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!