How do I define an empty table of unknown size?

79 vues (au cours des 30 derniers jours)
Fabrice Lambert
Fabrice Lambert le 26 Mai 2020
Hi,
I want to define an empty table to fill in a for loop. The size of the table is defined by another variable. How do I define the "VariableType" variable without knowing how many variables there are? In my case they will all be strings. Example:
T = table('Size', [2, numel(Elements)], 'VariableType',["string","string","string","string","string"]);
In this particular cae, numel(Elements) would be 5. But how do I define the table if I don't know numel(Elements) ?

Réponse acceptée

Steven Lord
Steven Lord le 26 Mai 2020
Elements = 1:5;
n = numel(Elements);
T = table('Size', [2 n], 'VariableTypes', repmat("string", 1, n))

Plus de réponses (1)

Walter Roberson
Walter Roberson le 26 Mai 2020
Sorry, variables that do not exist do not have any datatype.
As you add variables to the table, the datatype associated with the variable will be the determined by the datatype of the value being assigned. If necessary, string() the value you are assigning into the table.
  3 commentaires
Walter Roberson
Walter Roberson le 26 Mai 2020
That is not an empty table with an unknown number of variables: that is a table with 2 rows and a known number of variables.
Fabrice Lambert
Fabrice Lambert le 26 Mai 2020
Modifié(e) : Fabrice Lambert le 26 Mai 2020
In the example I gave, the number of variables is known for clearness' sake, yes. In practice "Elements" can be of variable length, so I need code that avoids fixed numbers of variables.

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