finding the nearest valaue

I have two sets of value 

s=

     38.9906   27.8590   18.6908   25.0184   27.5565   24.7551
     21.6141   30.9522   42.2398   52.9675   38.4323   45.0781
     39.3954   41.1888   39.0694   22.0141   34.0112   30.1668

S1= 19.0865
   36.2719
   44.6415

I HAVE to compare 1st value of S1 with first values of s and display them

for example the nearest value in s is 

   18.6908
  42.2398
  39.0694

please help

[Image Analyst]

What do you mean by the " first values of s"? It looks like you're identifying the entire column that contains the value of s closest to the first value of S1, so what does "first values of s" mean to you? To me the first value of s would be 38.9906.

By the way, is this your homework? (Sounds like a homework problem.)

Answer 1

[Matt J]

HINT:

 abs(bsxfun(@minus,s,S1));

[Jan]

+1: A good hint for a homework question. Thanks!

The term "nearest" is usually connected to the distance, e.g. the Euclidean norm.

Answer 2

[Azzi Abdelmalek]

s=[  38.9906   27.8590   18.6908   25.0184   27.5565   24.7551
   21.6141   30.9522   42.2398   52.9675   38.4323   45.0781
   39.3954   41.1888   39.0694   22.0141   34.0112   30.1668]
s1= [19.0865
 36.2719
 44.6415]
out=arrayfun(@(x) find(abs(s-s1(x))==min(min(abs(s-s1(x))))),1:numel(s1),'un',0)
out=s(cell2mat(out)')