Effacer les filtres
Effacer les filtres

Multiple Dice Rolls Help

3 vues (au cours des 30 derniers jours)
SB
SB le 21 Nov 2012
Commenté : nazar youssef le 15 Nov 2017
So basically, I have to write a function that simulates the rolling of a
given number of six sided dice a given number of times. The function should
take
two input arguments, the number of dice (NumDice) that will be rolled in each
experiment and the total number (NumRolls) of times that the dice will be
rolled. The output of the function will be a vector SumDice of length NumRolls
that contains the sum of the dice values in each experiment. I'll have to make
a histogram afterwards (which I havent done yet)
Here's what I've got so far, not sure how to make it a sum of dice:
% function SumDice=RollDice(NumDice,NumRolls)
distribution=zeros(6,1);
for roll=1:NumRolls
diceValues = randi(6,[NumDice 1]);
for die = 1 : NumDice
distribution(diceValues(die)) = distribution(diceValues(die)) +1;
end
end

Réponse acceptée

Walter Roberson
Walter Roberson le 21 Nov 2012
Sum of dice is just sum(diceValues). And you will not need the "for die" loop as you only get a single sum.
(By the way, the entire function can be done as a single expression, including the histogram.)
  4 commentaires
SB
SB le 21 Nov 2012
Could you maybe show an example? Vectorizing the summation as in within a vector using recursion or something?
Walter Roberson
Walter Roberson le 21 Nov 2012
sum() can be applied to arrays, not just to vectors.

Connectez-vous pour commenter.

Plus de réponses (1)

Harshit
Harshit le 21 Nov 2012
Here is what I feel will work fine
% function SumDice=RollDice(NumDice,NumRolls)
distribution=zeros(NumDice*6,1);
for roll=1:NumRolls
diceValues = randi(6,[NumDice 1]);
totaldiceValue = sum(diceValues);
distribution(totaldiceValue) = distribution(totaldiceValue) +1;
end
end
  1 commentaire
nazar youssef
nazar youssef le 15 Nov 2017
how to call the function?

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by