what is the function of this iteration

the figure on this link. http://salotungo.blogspot.de/
it is better we see it directly.
i want thelast data is n1 n2 n3 n4 so i can make plot directly. recently i did it manually one by one.
thx

4 commentaires

Image Analyst
Image Analyst le 22 Nov 2012
I don't know what this means: "i want thelast data is n1 n2 n3 n4" And what did you do manually?
uncung fgv
uncung fgv le 23 Nov 2012
n1,2,3 I mean the last calculation of (y3-y2)/(y2-y1)=n1;
(y4-y3)/(y3-y2)=n2;
and soon n3..7
i did it manually:
by calculating:
every difference of y1..7
and devide them also one another, one by one from plot to plot.
is there any simple function to calculate n1..7?
thx.
Daniel Shub
Daniel Shub le 23 Nov 2012
I am closing this question until the OP adds details.
uncung fgv
uncung fgv le 23 Nov 2012
the detail:
my problem is its iteration. manually it is ok. but i have many plots ánd datas.
i have a figure that have many plots within.
i want:
(y3-y2)/(y2-y1)=n1
(y4-y3)/(y3-y2)=n2
(y5-y4)/(y4-y3)=n3
(y6-y5)/(y5-y4)=n4
and soon until n7
the function of the figure is
w=8;
x=2;
a=0.2;
w=(0:0.3:3);
k=1; 1, 2,3,4,5,6,7 ; variable change
S=[1-exp(-a.*x.*k.*w)];
figure(1)
plot(w,S,'-+');
xlabel('w');
ylabel('S');
hold on
if we run this with k= 1, 2,3,4,5,6,7 we will find plots at one figure. and i want to calculate n1..n7 as above.

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