how to produce interval from this matrix?

Columns 1 through 6
0 0.1131 0.2134 0.3023 0.3812 0.4512
0 0.2134 0.3812 0.5132 0.6171 0.6988
0 0.3023 0.5132 0.6604 0.7631 0.8347
0 0.3812 0.6171 0.7631 0.8534 0.9093
0 0.4512 0.6988 0.8347 0.9093 0.9502
0 0.5132 0.7631 0.8847 0.9439 0.9727
0 0.5683 0.8136 0.9195 0.9653 0.9850
i want interval between column 2 and 1
column 3 and 2
column 4 and 3
column 5 and 4
column 6 and 5
and then i want
the result of those interval devided each other like:
interval column 3 and 2/ interval column 2 and 1
interval column 4 and 3/ interval column 3 and 2
interval column 5 and 4/ interval column 4 and 3
and soon

2 commentaires

per isakson
per isakson le 23 Nov 2012
Azzi, I guess "so on". However, what does OP mean by "interval"?
uncung fgv
uncung fgv le 24 Nov 2012
sorry my native not english. interval in my mind is determination or different-ial. like 6 and 4 the 'interval'= 2 (minus)

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 Réponse acceptée

Matt J
Matt J le 24 Nov 2012
Modifié(e) : Matt J le 24 Nov 2012
Here's a wild guess at what you mean
diff(A(:,2:end),1,2)./diff(A(:,1:end-1),1,2)

4 commentaires

uncung fgv
uncung fgv le 24 Nov 2012
i will try this. thx. i ll be back.
uncung fgv
uncung fgv le 24 Nov 2012
you solve my problem excelently. thank you very much.
Matt J
Matt J le 24 Nov 2012
Modifié(e) : Matt J le 24 Nov 2012
A little more efficiently, then
temp=diff(A,1,2);
out=temp(:,2:end)./temp(:,1:end-1);
uncung fgv
uncung fgv le 24 Nov 2012
many thanks. gratefull i know this site.

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