How can I sort data like this?

9 vues (au cours des 30 derniers jours)
Husni
Husni le 24 Nov 2012
I have data like this:
A= [6.5048 + 4.7841i
6.5048 - 4.7841i
1.2539 + 3.7939i
1.2539 - 3.7939i
-3.0305 + 3.2324i
-3.1216 + 5.9919i
-3.0305 - 3.2324i
-3.1216 - 5.9919i];
how can I sort to be following:
A= [6.5048 + 4.7841i
6.5048 - 4.7841i
1.2539 + 3.7939i
1.2539 - 3.7939i
-3.0305 + 3.2324i
-3.0305 - 3.2324i
-3.1216 + 5.9919i
-3.1216 - 5.9919i];
where all data are followed directly by the conjugates?
Best regard
Ali
  2 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 24 Nov 2012
How are they sorted?
Husni
Husni le 24 Nov 2012
I am sorry it is not clear, they sorted based on this: first data is 6.5048 + 4.7841i, it then will be followed by its conjugate 6.5048 - 4.7841i which automatically becomes second data. the third data is 1.2539 + 3.7939i and will be followed by 1.2539 - 3.7939i (third & fourth data). The fifth data is -3.0305 + 3.2324i.but in the original data, the conjugate of fifth does not follow, therefore its should be reordered. I hope it is clear?

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Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 24 Nov 2012
  5 commentaires
Husni
Husni le 24 Nov 2012
Sorry, I try to find good way to explain. Imagine that A is complex power. I want to sort this. The top element has energy 6.5048 + 4.7841i and its complex conjugate 6.5048 - 4.7841i. the second element has energy 1.2539 + 3.7939i and its conjugate 1.2539 - 3.7939i. the third element has energy -3.0305 + 3.2324i but the following data is not its conjugate. Its conjugate locates at data number 7. so the 7 th data is moved to 5 th data (since it is the conjugate of -3.0305 + 3.2324i ) and so on. hopefully it is quite clear :-)
many thanks anyway :-)
Matt Fig
Matt Fig le 24 Nov 2012
See my solution below.

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Plus de réponses (2)

Matt Fig
Matt Fig le 24 Nov 2012
Modifié(e) : Matt Fig le 24 Nov 2012
You need more than to simply call SORT. The SORT function sorts complex arrays by magnitude, which is a problem for an array like this:
A = [2+3i;
3+2i;
sqrt(13/2)+sqrt(13/2)*i;
2-3i;
3-2i;
sqrt(13/2)-sqrt(13/2)*i]
% Note all(abs(A)==sqrt(13))
For problems like this you need to do something more involved.
[RA,J] = sort(real(A));
% Now we can put them together
newA = complex(RA,imag(A(J)))
  1 commentaire
Husni
Husni le 24 Nov 2012
Thanks matt, I got idea from your code

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Azzi Abdelmalek
Azzi Abdelmalek le 24 Nov 2012
Modifié(e) : Azzi Abdelmalek le 24 Nov 2012
try this
B=A
while length(A)>0;
idx=find(A==conjug(A(1)));
B(ii)=A(1);
B(ii+1)=A(idx);
A(idx)=[];
A(1)=[];
ii=ii+2;
end
  1 commentaire
Husni
Husni le 24 Nov 2012
Thanks Azzi for your help :-)

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