adding column in text file with value

Suppose i have a text file that contains 1 column, 68160 rows of random data.
Now, i want
for first 480 rows add 0 in first column,
next 480 rows add 5,
next 480 rows add 10,
next 480 rows add 15,
and continue this with increment of 5, until all columns get finished.. and store all this new data in second column...
I want to write MATLAB code.. So, how to do it...?

 Réponse acceptée

Muruganandham Subramanian
Muruganandham Subramanian le 27 Nov 2012
Modifié(e) : Muruganandham Subramanian le 27 Nov 2012
Check the below code: a=zeros(68160,1);
k=480;
l=5;
j=1;
for i=1:numel(a)
if i<=k
a(i)=a(i)+0;
else
if i <= (j+1)*k
a(i)=a(i)+j*l;
else
j=j+1;
a(i)=a(i)+j*l;
end
end
end

Plus de réponses (1)

Jan
Jan le 27 Nov 2012

0 votes

At first you have to read the file. Therefore you have to know the format of the contents: "random data" could be nearly everything, e.g. floating point numbers like 0.1098435, integers like 134, strings like 'ajdtaoieurgkjahsvbdk', etc. "Adding 0" might imply that you are talking about integer values.
Then a loop seems to be the easiest solution. Just try it and return to the forum in case of problems. It is much easier for the forum users to suggest improvements than to write the complete program from scratch.

1 commentaire

Lalit Patil
Lalit Patil le 27 Nov 2012
I got it solved...!
clear all;
clc;
fid = fopen('data.txt','wt');
for j=1:500
fprintf(fid,'%f\n',j);
end
fclose(fid);
fileID = fopen('data.txt');
C = textscan(fileID, '%f32');
fclose(fileID);
x=cell2mat(C(:,1));
for m = 0:49
for k = (1+(10*m)):(10+(10*m))
y(k) = x(k) + (0+(5*m));
end
end
y = y';
fid = fopen('data.txt','wt');
for j=1:500
fprintf(fid,'%f %f\n',j,y(j));
end
fclose(fid);
If it is possible to short this code then suggest me...

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