Using Find() in For Loop

I am setting up a very simple matlab code to find the first value in each column of a matrix that passes a threshold value. If the matrix has a value that meets the threshold range, then it outputs an index. If the condition is not met, 'NaN' appears.The expected outcome is 1-by-5 matrix that has indice for each column.

However, I could not get IF statement to work. Each line of the code works fine but when it is put together, it does not produce the values I was expecting.

What am I missing here?

xn=[1 0 16 14 18;0 13 4 0 11; 0 4 15 1 52; 0 5 5 17 43; 0 11 5 3 14];

y=[1 24 35 15 16]; %Threshold

t=4*ones(2,5);

SD=1.5;

y_minuse_SD=y-SD*ones(1,5);

y_plus_SD=y+SD*ones(1,5);

d=1:length(xn);   

for s=1:5;

     if xn(d,s)<y_plus_SD(1,s) & xn(d,s)>=y_minuse_SD(1,s)
          t(1,s)=find(xn(d,s)>=y_minuse_SD(1,s),1);
      else
          t(1,s)=NaN;
      end
  end

[Azzi Abdelmalek]

What is the expected value?

Answer 1

[Azzi Abdelmalek]

 xn=[1 0 16 14 18;0 13 4 0 11; 0 4 15 1 52; 0 5 5 17 43; 0 11 5 3 14];
y=[1 24 35 15 16]; %Threshold
[n,m]=size(xn);
SD=1.5;
y_m=y-SD;
y_p=y+SD;
z=xn(:);
out=arrayfun(@(x) find(z<y_p(x) & z>y_m(x),1),1:n,'un',0)
out(cellfun(@isempty,out))=num2cell(nan)